Optimal. Leaf size=192 \[ \frac{2 a \left (8 a^2-3 b^2\right ) \tan ^5(c+d x)}{105 d}+\frac{4 a \left (8 a^2-3 b^2\right ) \tan ^3(c+d x)}{63 d}+\frac{2 a \left (8 a^2-3 b^2\right ) \tan (c+d x)}{21 d}+\frac{2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac{2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{63 d}+\frac{\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d} \]
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Rubi [A] time = 0.221397, antiderivative size = 192, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.19, Rules used = {2691, 2861, 2669, 3767} \[ \frac{2 a \left (8 a^2-3 b^2\right ) \tan ^5(c+d x)}{105 d}+\frac{4 a \left (8 a^2-3 b^2\right ) \tan ^3(c+d x)}{63 d}+\frac{2 a \left (8 a^2-3 b^2\right ) \tan (c+d x)}{21 d}+\frac{2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac{2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (\left (4 a^2-b^2\right ) \sin (c+d x)+3 a b\right )}{63 d}+\frac{\sec ^9(c+d x) (a \sin (c+d x)+b) (a+b \sin (c+d x))^2}{9 d} \]
Antiderivative was successfully verified.
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Rule 2691
Rule 2861
Rule 2669
Rule 3767
Rubi steps
\begin{align*} \int \sec ^{10}(c+d x) (a+b \sin (c+d x))^3 \, dx &=\frac{\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}-\frac{1}{9} \int \sec ^8(c+d x) (a+b \sin (c+d x)) \left (-8 a^2+2 b^2-6 a b \sin (c+d x)\right ) \, dx\\ &=\frac{\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac{2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac{1}{63} \int \sec ^6(c+d x) \left (6 a \left (8 a^2-3 b^2\right )+10 b \left (4 a^2-b^2\right ) \sin (c+d x)\right ) \, dx\\ &=\frac{2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac{\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac{2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac{1}{21} \left (2 a \left (8 a^2-3 b^2\right )\right ) \int \sec ^6(c+d x) \, dx\\ &=\frac{2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac{\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac{2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}-\frac{\left (2 a \left (8 a^2-3 b^2\right )\right ) \operatorname{Subst}\left (\int \left (1+2 x^2+x^4\right ) \, dx,x,-\tan (c+d x)\right )}{21 d}\\ &=\frac{2 b \left (4 a^2-b^2\right ) \sec ^5(c+d x)}{63 d}+\frac{\sec ^9(c+d x) (b+a \sin (c+d x)) (a+b \sin (c+d x))^2}{9 d}+\frac{2 \sec ^7(c+d x) (a+b \sin (c+d x)) \left (3 a b+\left (4 a^2-b^2\right ) \sin (c+d x)\right )}{63 d}+\frac{2 a \left (8 a^2-3 b^2\right ) \tan (c+d x)}{21 d}+\frac{4 a \left (8 a^2-3 b^2\right ) \tan ^3(c+d x)}{63 d}+\frac{2 a \left (8 a^2-3 b^2\right ) \tan ^5(c+d x)}{105 d}\\ \end{align*}
Mathematica [A] time = 1.59264, size = 299, normalized size = 1.56 \[ \frac{\sec ^9(c+d x) \left (3150 b \left (23 b^2-147 a^2\right ) \cos (c+d x)-308700 a^2 b \cos (3 (c+d x))-132300 a^2 b \cos (5 (c+d x))-33075 a^2 b \cos (7 (c+d x))-3675 a^2 b \cos (9 (c+d x))+3440640 a^2 b+2064384 a^3 \sin (c+d x)+1376256 a^3 \sin (3 (c+d x))+589824 a^3 \sin (5 (c+d x))+147456 a^3 \sin (7 (c+d x))+16384 a^3 \sin (9 (c+d x))+3096576 a b^2 \sin (c+d x)-516096 a b^2 \sin (3 (c+d x))-221184 a b^2 \sin (5 (c+d x))-55296 a b^2 \sin (7 (c+d x))-6144 a b^2 \sin (9 (c+d x))-737280 b^3 \cos (2 (c+d x))+48300 b^3 \cos (3 (c+d x))+20700 b^3 \cos (5 (c+d x))+5175 b^3 \cos (7 (c+d x))+575 b^3 \cos (9 (c+d x))+409600 b^3\right )}{10321920 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.118, size = 265, normalized size = 1.4 \begin{align*}{\frac{1}{d} \left ( -{a}^{3} \left ( -{\frac{128}{315}}-{\frac{ \left ( \sec \left ( dx+c \right ) \right ) ^{8}}{9}}-{\frac{8\, \left ( \sec \left ( dx+c \right ) \right ) ^{6}}{63}}-{\frac{16\, \left ( \sec \left ( dx+c \right ) \right ) ^{4}}{105}}-{\frac{64\, \left ( \sec \left ( dx+c \right ) \right ) ^{2}}{315}} \right ) \tan \left ( dx+c \right ) +{\frac{{a}^{2}b}{3\, \left ( \cos \left ( dx+c \right ) \right ) ^{9}}}+3\,a{b}^{2} \left ( 1/9\,{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{ \left ( \cos \left ( dx+c \right ) \right ) ^{9}}}+2/21\,{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{ \left ( \cos \left ( dx+c \right ) \right ) ^{7}}}+{\frac{8\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{105\, \left ( \cos \left ( dx+c \right ) \right ) ^{5}}}+{\frac{16\, \left ( \sin \left ( dx+c \right ) \right ) ^{3}}{315\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}} \right ) +{b}^{3} \left ({\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{9\, \left ( \cos \left ( dx+c \right ) \right ) ^{9}}}+{\frac{5\, \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{63\, \left ( \cos \left ( dx+c \right ) \right ) ^{7}}}+{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{21\, \left ( \cos \left ( dx+c \right ) \right ) ^{5}}}+{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{63\, \left ( \cos \left ( dx+c \right ) \right ) ^{3}}}-{\frac{ \left ( \sin \left ( dx+c \right ) \right ) ^{4}}{63\,\cos \left ( dx+c \right ) }}-{\frac{ \left ( 2+ \left ( \sin \left ( dx+c \right ) \right ) ^{2} \right ) \cos \left ( dx+c \right ) }{63}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.981288, size = 196, normalized size = 1.02 \begin{align*} \frac{{\left (35 \, \tan \left (d x + c\right )^{9} + 180 \, \tan \left (d x + c\right )^{7} + 378 \, \tan \left (d x + c\right )^{5} + 420 \, \tan \left (d x + c\right )^{3} + 315 \, \tan \left (d x + c\right )\right )} a^{3} + 3 \,{\left (35 \, \tan \left (d x + c\right )^{9} + 135 \, \tan \left (d x + c\right )^{7} + 189 \, \tan \left (d x + c\right )^{5} + 105 \, \tan \left (d x + c\right )^{3}\right )} a b^{2} - \frac{5 \,{\left (9 \, \cos \left (d x + c\right )^{2} - 7\right )} b^{3}}{\cos \left (d x + c\right )^{9}} + \frac{105 \, a^{2} b}{\cos \left (d x + c\right )^{9}}}{315 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.38494, size = 347, normalized size = 1.81 \begin{align*} -\frac{45 \, b^{3} \cos \left (d x + c\right )^{2} - 105 \, a^{2} b - 35 \, b^{3} -{\left (16 \,{\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{8} + 8 \,{\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{6} + 6 \,{\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{4} + 35 \, a^{3} + 105 \, a b^{2} + 5 \,{\left (8 \, a^{3} - 3 \, a b^{2}\right )} \cos \left (d x + c\right )^{2}\right )} \sin \left (d x + c\right )}{315 \, d \cos \left (d x + c\right )^{9}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.13864, size = 639, normalized size = 3.33 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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